Answer :
Answer: Choice B
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Explanation:
Anything with a y^2 in it is immediately ruled out due to the fact that something like y^2 = x solves to y = x or y = -x. Or in shorthand you would write [tex]y = \pm x[/tex]. The "plus or minus" means we have two equations squished into one, so to speak. So it is possible for an x input to lead to more than one output here. The same applies to choice A and choice D, which we can cross off the list.
We can also cross off choice C for the same reason. The x = 3 input leads to outputs y = 2 and y = 7 at the same time.
A function is only possible if every x input leads to exactly one y output, assuming the x input is defined in the domain of course. Only choice B satisfies this requirement. Each x input (13, 2, and -1) leads to exactly one y output.
Answer: Domain Range
13 0
Step-by-step explanation:
Anything with a y^2 in it is immediately ruled out due to the fact that something like y^2 = x solves to y = x or y = -x. Or in shorthand you would write . The "plus or minus" means we have two equations squished into one, so to speak. So it is possible for an x input to lead to more than one output here. The same applies to choice A and choice D, which we can cross off the list.
We can also cross off choice C for the same reason. The x = 3 input leads to outputs y = 2 and y = 7 at the same time.
A function is only possible if every x input leads to exactly one y output, assuming the x input is defined in the domain of course. Only choice B satisfies this requirement. Each x input (13, 2, and -1) leads to exactly one y output.