Answer :
Let the shortest leg be x feet;
The other leg will be (x + 14) feet.
Using Pythagoras theorem;
x^2 +(x+14)^2 = 26^2
x^2 + x^2 +28x + 196 = 676
2x^2 + 28x - 480 = 0
x^2 + 14x - 240 = 0
x^2 +24x - 10x -240 = 0
x(x+24) - 10(x+24) = 0
(x+24)(x-10)= 0;
x=10;
x+14 = 24
Hence, the length of the legs are 10 feet and 24 feet.
The other leg will be (x + 14) feet.
Using Pythagoras theorem;
x^2 +(x+14)^2 = 26^2
x^2 + x^2 +28x + 196 = 676
2x^2 + 28x - 480 = 0
x^2 + 14x - 240 = 0
x^2 +24x - 10x -240 = 0
x(x+24) - 10(x+24) = 0
(x+24)(x-10)= 0;
x=10;
x+14 = 24
Hence, the length of the legs are 10 feet and 24 feet.