Answer :
Answer:
80.32 °C
Explanation:
The difference in the boiling point is
ΔT= Kb * m
m stands for molality, moles of solute (in this case eugenol) divided by kg of solvent (in this case benzene).
We're given Kb already, so in order to calculate ΔT we calculate m first:
- 10.0 g of benzene = 0.01 kg bencene
- The molecular weight of eugenol is 12*10 + 12*1 + 2*16 = 164 g/mol
- 0.144 g eugenol ÷ 164 g/mol = 8.78 *10⁻⁴ mol eugenol.
m = 8.78 *10⁻⁴ mol / 0.01 kg = 0.0878 m
Finally we calculate ΔT:
ΔT = 2.53 °C/m * 0.0878 m = 0.22 °C
Thus the boiling point of the solution is
T₂ = T₁ + ΔT
T₂ = 80.10°C + 0.22°C
T₂ = 80.32 °C
The elevation in the boiling point with the addition of eugenol in the solution has been 0.22 degree Celsius, and the new boiling point is 80.32 degree Celsius.
What is boiling point?
The boiling point can be given as the temperature at which the liquid has been converted to vapors. The change in temperature with the addition of solution is given as:
[tex]\Delta T=Kb\;\times\;m[/tex]
The molality (m) of the solution of 10 g (0.01 kg) benzene solution has been:
[tex]m=\rm\dfrac{mass}{molar\;mass}\;\times\;\dfrac{1000}{mass\;of\;solvent} \\\\\textit m=\dfrac{0.144}{164}\;\times\;\dfrac{1000}{10}\\\\ \textit m=0.0878\;m[/tex]
The change in temperature can be given as:
[tex]\Delta T=0.0878\;\times\;2.53\\\Delta T=0.22\;^\circ \text C[/tex]
The new temperature of the solution is given as;
[tex]\rm New\;temperature=Initial\;temperature+\Delta \textit T\\\\New\;temperature=80.10\;+\;0.22\;^\circ C\\\\New\;temperature=80.32\;^\circ C[/tex]
The final temperature of the eugenol solution in benzene has been 80.32 degree Celsius.
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