Answer :
Answer:
Y = [tex]\frac{X}{3} - 9[/tex]
Step-by-step explanation:
Given equation of first line as
Y = -3X + 4
Slop of the first line (m1) = -3
As first line is parallel to second line , then (m1) × (m2) = - 1
i.e m2 = [tex]\frac{-1}{m1}[/tex]
m2 = [tex]\frac{-1}{-3}[/tex]
m2 = [tex]\frac{1}{3}[/tex]
Now equation of seconf line with points (9 , -6) and slop [tex]\frac{1}{3}[/tex]
i.e equation of new line Y - y1 = m2 (X - x1)
Y + 6= [tex]\frac{1}{3}[/tex]
Y = [tex]\frac{X}{3} - \frac{9}{3} - 6[/tex]
Hence equation of new line is
Y = [tex]\frac{X}{3} - 9[/tex] Answer