Answer :
Answer:
0
Explanation:
Given:
initial velocity, [tex]u=1300 km.hr^{-1}[/tex]
distance of telescope from the launch pad, [tex]d=13 km[/tex]
time after which the observation starts, t = 3 min.
Now, from the equation of motion:
[tex]s=u.t-\frac{1}{2} g.t^{2}[/tex]
[tex]s= (1300\times \frac{5}{18}) \times (3\times 60)- \frac{1}{2} \times 9.8\times (3\times 60)^{2}[/tex]
[tex]s=-93760 m[/tex]
Which indicates that the after the given time the rocket would have fallen down on the ground if it did not had an acceleration of its own.