Answer :
Answer
given,
mass of the cat = 8 kg
length of the ramp = 2 m
inclined at = 19°
force exerted = 60 N
cat is moving at speed = 2 m/s
velocity when it reaches at the top = ?
using work energy theorem
work done by the gravity = - mgL sin θ
total work (w)
= F x - mgL sin θ
= 60 x 2 - 8 x 9.8 x 2 sin 19°
= 68.95 J
initial kinetic energy
[tex]K E_i = \dfrac{1}{2}mv_i^2[/tex]
[tex]K E_i = \dfrac{1}{2}\times 8 \times 2^2[/tex]
[tex]K E_i = 16\ J[/tex]
change in kinetic energy is work done
[tex]K_f - K_i = W[/tex]
[tex]\dfrac{1}{2}mv^2 = W+k_i[/tex]
[tex]v = \sqrt{\dfrac{2(W+k_i)}{m}}[/tex]
[tex]v = \sqrt{\dfrac{2(68.95+16)}{8}}[/tex]
v = 4.61 m/s