Answer :
Answer: C x -4y = -16
Step-by-step explanation:
Slope=∆y/∆x
M=y-y1/x-x1
M=1/4, y1 =2,x1=-8
1/4=y-2/x-(-8)
1/4=y-2/x+8
Cross multiply
4(y-2)=x+8
4y -8 = x + 8
-8-8= x - 4y
x +4y = -16 answer
Option A and Option C
The equation of a line with the slope of 1/4 that passes through the point (-8,2) is [tex]y-2=\frac{1}{4}(x+8)[/tex] or x - 4y = -16
Solution:
Given that the line passes through (-8, 2)
Slope is given as [tex]\frac{1}{4}[/tex]
Equation of line passing through point [tex](x_1, y_1)[/tex] and having slope “m” is given as:
[tex]\left(y-y_{1}\right)=m \times\left(x-x_{1}\right)[/tex]
Plugging in the values [tex]x_1 = -8 ; y_1 = 2 ; m = \frac{1}{4}[/tex]
[tex]\begin{array}{l}{y-2=\frac{1}{4}(x-(-8))} \\\\ {y-2=\frac{1}{4}(x+8)}\end{array}[/tex]
4y - 8 = x + 8
x - 4y = -16
Hence Option A and Option C is correct