Answer:
The intensity of the first earthquake is 6.31 times the second one
Step-by-step explanation:
The given formulae is M=log([tex]\frac{I}{S}[/tex])
Here for both the earthquakes the value of S is same.
Let the Intensity of the first earthquake be I1 and the second be I2.
Given M1=7.5
M2=6.7
Now M1=log([tex]\frac{I1}{S}[/tex])------1
M2=log([tex]\frac{I2}{S}[/tex])-----2
Now subtract 1 and 2 we get
M1-M2=log([tex]\frac{I1}{I2}[/tex])
I1/I2=[tex]10^{M1-M2}[/tex]
I1=I2([tex]10^{0.8}[/tex]
I1=I2*6.31
