Answer :
Answer:
Explanation:
Given
mass of block=21 kg
inclination [tex]\theta =25^{\circ}[/tex]
t=1.51 s
total acceleration [tex]a=g\sin \theta =9.8\times \sin (25)=4.14 m/s^2[/tex]
[tex]v=u+at[/tex]
[tex]v=0+4.14\times 1.51=6.25 m/s[/tex]
[tex]v^2-u^2=2 as [/tex]
[tex]6.25^2-0=2\times 4.14\times s[/tex]
[tex]s=4.72 m[/tex]
Answer:
s = 4.71 m
Explanation:
given,
mass of the block = 21 kg
angle θ = 25◦
time to slide = 1.51 s
acceleration = 9.8 m/s²
distance = ?
acceleration = a sin θ
= 9.8 sin 25° = 4.14 m/s²
[tex]s = ut + \dfrac{1}{2}at^2[/tex]
[tex]s = \dfrac{1}{2}\times 4.14\times 1.51^2[/tex]
s = 4.71 m
hence, the distance traveled by the block = 4.71 m