Answer:
[tex]42000[1+(1.04)^{1}+(1.04)^{2} +(1.04)^{3} + ....... + (1.04)^{n-1} ][/tex]
Step-by-step explanation:
Harmony earns 42000 salaries in the first year of her career and each year she gets a 4% rise in her income.
Therefore, in the second year she will get [tex]42000[1+\frac{4}{100} ]^{1} = 42000[1.04][/tex].
In the third year she will earn [tex]42000[1.04]^{2}[/tex]
In the fourth year she will earn [tex]42000[1.04]^{3}[/tex]
In this manner she will earn a total of
[tex]42000[1+(1.04)^{1}+(1.04)^{2} +(1.04)^{3} + ....... + (1.04)^{n-1} ][/tex] in her forst n years of her career. (Answer)
Answer:
42000(1-1.04^n/-0,04)
Step-by-step explanation: