If CF = 5, CD = 12, and EF = 5, what is the perimeter of triangle CDE?

Answer:
The perimeter of triangle CDE is 34.
Step-by-step explanation:
To find the perimeter of a triangle, you have to add all the sides together, since this looks like a isosceles triangle, you would make side ED also 12 and then just add them all together.
12+12+5+5= 34.
The perimeter of a triangle is the sum of its side lengths.
The perimeter of triangle CDE is 34
The given parameters are:
[tex]\mathbf{CF = 5}[/tex]
[tex]\mathbf{CD = 12}[/tex]
[tex]\mathbf{EF = 5}[/tex]
From the attached figure, the perimeter of CDE is
[tex]\mathbf{Perimeter = CF + EF + CD + DE}[/tex]
Where:
CD = DE = 12
So, we have:
[tex]\mathbf{Perimeter = 5 + 5 + 12 + 12}[/tex]
[tex]\mathbf{Perimeter = 34}[/tex]
Hence, the perimeter of triangle CDE is 34
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