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A skateboard is moving to the right with a velocity of 8 m/s after a steady Gust of wind that last 5 seconds the skateboarder is moving to the right with a velocity of 5 m/s assuming the acceleration is constant what is the acceleration of the skateboard during the five second time.

Answer :

skyluke89

The acceleration of the skateboard is [tex]-0.6 m/s^2[/tex] (to the left)

Explanation:

The motion of the skateboard is a uniformly accelerated motion, so we can use the following suvat equation:

[tex]v=u+at[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the skateboard in this problem, choosing right as positive direction, we have:

u = +8 m/s is the initial velocity

v = +5 m/s is the final velocity

t = 5 s is the time

Solving for a, we find the acceleration:

[tex]a=\frac{v-u}{t}=\frac{5-8}{5}=-0.6 m/s^2[/tex]

And since the sign is negative, the direction is to the left.

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