Answer :
Answer:
4370.83044 m²
Explanation:
[tex]W_{net}[/tex] = Net work done = 570 kW
[tex]T_l[/tex] = Low temperature resrvoir = 20 °C
A = Area of solar collector
Amount of solar heat received = [tex]Q_h[/tex] = 0.315A
[tex]\eta_{th}=\eta_{Carnot}=1-\frac{T_l}{T_h}\\\Rightarrow \eta_{th}=1-\frac{20+273}{500}\\\Rightarrow \eta_{th}=1-0.586\\\Rightarrow \eta_{th}=0.414[/tex]
[tex]\eta_{th}=\frac{W_{net}}{Q_h}\\\Rightarrow Q_h=\frac{W_{net}}{\eta_{th}}\\\Rightarrow Q_h=\frac{570}{0.414}\\\Rightarrow Q_h=1376.81159\ kW[/tex]
[tex]Q_h=0.315A\\\Rightarrow A=\frac{Q_h}{0.315}\\\Rightarrow A=\frac{1376.81159}{0.315}\\\Rightarrow A=4370.83044\ m^2[/tex]
The theoretical minimum solar collector area required is 4370.83044 m²