Answer :
Answer:
P=900W
Explanation:
We need to define a variable, where the system can be used without tripping the circuit.
So we define,
[tex]P_{A} = VI[/tex]
Making the substitution for [tex]V=120V[/tex] and [tex]I=20A[/tex], we can find [tex]P_{A}[/tex],
[tex]P_{A} = (120V)(20A)\\P_{A} = 2400W[/tex]
We know as well that the power required to operate is 1500W(P_{B}, so
P=P_{A}-P_{B}
Making the substitution for the values we have,
[tex]P=2400W-1500W\\P=900W[/tex]
So we found the power setting at which the circuit breaker trips.