Answer :
Answer:
[tex]\tau=0.675\ Nm[/tex]
Explanation:
It is given that,
Mass of the meter stick, m = 0.3 kg
Meter stick is located at its 48 cm mark, l = 48 cm
We need to find the magnitude of the torque if it is supported at the 25-cm mark, l' = 25 cm
It is given by :
[tex]\tau=mgl[/tex]
[tex]\tau=0.3\ kg\times 9.79\ m/s^2\times 0.23\ m[/tex]
[tex]\tau=0.675\ Nm[/tex]
So, the magnitude of the torque is 0.675 N-m. Hence, this is the required solution.
The magnitude of the torque due to gravity if it is supported at the 25cm is 0.68N/m².
How to calculate magnitude of torque?
The magnitude of torque (r) can be calculated by using the following formula:
r = mgL
Where;
- r = magnitude of torque
- m = mass
- g = acceleration due to gravity
- L = length
Mass of the meter stick, m = 0.3 kg
Meter stick is located at its 48 cm mark, l = 48 cm - 25 = 23cm
r = 0.3 × 9.8 × 0.23
r = 0.68N/m²
Therefore, the magnitude of the torque due to gravity if it is supported at the 25cm is 0.68N/m².
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