Answer:
B. [tex] \dfrac{3\sqrt{2}}{2} [/tex]
Step-by-step explanation:
The sides forming the right angle are called the legs. Since the two angles shown are congruent, the legs are congruent.
We can use the Pythagorean theorem.
[tex] a^2 + b^2 = c^2 [/tex]
[tex] x^2 + x^2 = 3^2 [/tex]
[tex] 2x^2 = 9 [/tex]
[tex] x^2 = \dfrac{9}{2} [/tex]
[tex] x = \sqrt{\dfrac{9}{2}} [/tex]
[tex] x = \dfrac{3}{\sqrt{2}} [/tex]
[tex] x = \dfrac{3}{\sqrt{2}} \times \dfrac{\sqrt{2}}{\sqrt{2}} [/tex]
[tex] x = \dfrac{3\sqrt{2}}{\sqrt{2}\sqrt{2}} [/tex]
[tex] x = \dfrac{3\sqrt{2}}{2} [/tex]
ayyyy
2019 2020 sucks
2019 2020 sucks
2019 2020 sucks
(sorry i was going to answer then saw free points :D)
