Answer :
If all three were the same, then each one would be (279/3) or 93. The integers would be 93, 93, and 93.
Great ! Just take 1 away from the first one, and stick it onto the last one. Now you have 92, 93, 94, and the sum is still the same 279.
Answer:
[tex]\huge{\boxed{~~Answer:92,93,94~~}}[/tex]
Step-by-step explanation:
→ [tex]The~sum~of~three~consecutive~integers~is~279.[/tex]
[tex]Let~one~number~be~``x"[/tex]
→ [tex]Therefore,~other~ numbers~ will~ be~ (x+1)~ and ~(x+2),~since,~consecutive~[/tex] [tex]means~ one ~after~ the~ other.[/tex]
[tex]x+(x+1)+(x+2)=279[/tex]
[tex]Implies ~3x +1+2=279\\Implies ~3x+3=279\\Implies ~3x =279-3\\Implies ~3x =276[/tex]
[tex]Implies~x=\frac{276}{3} =92[/tex]
→ [tex]Therefore,~x= 92[/tex]
[tex](x+1)=92+1=93\\(x+2)=93+2=94[/tex]
→ [tex]So,~the~integers~are:92,93~and~94![/tex]