Answer :
Answer:
Confidence interval for the population variance = (0.7476,1.6516)
Step-by-step explanation:
We are given the following information in the question:
n = 25
Sample mean, [tex]\bar{x}[/tex] = 29.530 inches
Alpha, α = 0.05
Sample standard deviation, s = 1.0953 inches
Confidence interval:
[tex]s^2 \pm t_{critical}\frac{s}{\sqrt{n}}[/tex]
Putting the values, we get,
[tex]t_{critical}\text{ at degree of freedom 24 and at}~\alpha_{0.05} = \pm 2.0638[/tex]
[tex](1.0953)^2 \pm 2.0638(\frac{1.0953}{\sqrt{25}} ) = 1.1996 \pm 0.452 = (0.7476,1.6516)[/tex]