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Two fun-loving otters are sliding toward each other on a muddy (and hence frictionless) horizontal surface. One of them, of mass 8.50 kg , is sliding to the left at 6.00 m/s, while the other, of mass 5.35 kg , is slipping to the right at 6.00 m/s. They hold fast to each other after they collide. Part A Find the magnitude of the velocity of these free-spirited otters right after they collide. | AEO o a ? m/s

Answer :

Answer:

v = -1.36 m/s

Explanation:

It is given that,

Mass of object 1, [tex]m_1=8.5\ kg[/tex]

Speed of mass 1, [tex]v_1=-6\ kg[/tex] (left)

Mass of object 2, [tex]m_2=5.35\ kg[/tex]

Speed of mass 2, [tex]v_2=6\ kg[/tex] (right)

It is the case of inelastic collision. Let v is the final speed of both objects after the collision. Using the conservation of momentum as :

[tex]v=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}[/tex]

[tex]v=\dfrac{8.5\times (-6)+5.35\times 6}{8.5+5.35}[/tex]

v = -1.36 m/s

So, the velocity of these free-spirited otters is 1.36 m/s towards left. Hence, this is the required solution.

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