Answer :
Answer:
B) be narrower than the current interval width
Step-by-step explanation:
Given that a 95% confidence interval for μ has been constructed.
This confidence interval would depend on the margin of error which in turn depends on the standard error and sample size.
Margin of error = Critical value *std dev/ sqrt of sample size n
Hence when sample size increases, n increases so square root of n increases, which in turn decreases the margin of error.
So confidence interval would become narrower.
B) be narrower than the current interval width