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a plane lands on the runway and slows from 758km/hr to 30km/hr in 0.013 hours what is the planes acceleration?

Answer :

Answer:

a = -56000 Km/h²

Explanation:

Given,

The initial speed of the plane, u = 738 Km/h

The final speed of the plane, v = 30 Km/h

The time period of the travel, t = 0.013 h

The acceleration of a body equal to the difference between the final and initial velocity to the time period of travel.

The formula for acceleration,

                                      a = (v - u) / t

                                          = (30 - 738) / 0.013

                                          = -56000 Km/hr²

The negative sign indicates that the plane is decelerating.

The acceleration of the plane is, a = -56000 Km/hr²

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