Answer :
Answer:
-4.769x
Explanation:
In order to develop the problem it is necessary to bring up the concepts related to Eyepiece or Focal Length of an ocular lens, i. e, the distance from the principal plane of the eyepiece where parallel rays of light converges to a single point. The equation is given by,
[tex]f_e = \frac{N}{M_e}[/tex]
Where,
N= Near point
[tex]M_e=[/tex]Magnification
[tex]f_e =[/tex]Focal length
By replacing the values we can obtain that:
[tex]f_e = \frac{26}{3}[/tex]
[tex]f_e = 8.667cm[/tex]
It is then possible to find the magnification of the telescope with the previous data found through
[tex]M= 1-\frac{l}{f_e}[/tex]
[tex]M= 1- \frac{50}{8.667}[/tex]
[tex]M = -4.769[/tex]