Answer: The initial velocity is - 44
Step-by-step explanation:
S = [tex]\frac{-31}{2}[/tex][tex]t^{2}[/tex] - 44t + 85 .
Differentiating once to get the velocity , we have
V = - 31t - 44
The initial velocity means that t = 0 , substitute this into the equation , we have
V = -31 (0) - 44
V = -44
Therefore, the initial velocity is -44
Answer : The correct option is, The initial velocity is -44
Step-by-step explanation :
As we are given the position function expression:
[tex]S=-\frac{31}{2}t^2-44t+85[/tex]
As we know that, differentiation of position function with respect to 't' gives velocity function.
[tex]\frac{dS}{dt}=\frac{d(-\frac{31}{2}t^2-44t+85)}{dt}[/tex]
[tex]v=-2\times \frac{31}{2}t-44[/tex]
[tex]v=-31t-44[/tex]
At time t = 0, the initial velocity will be:
[tex]v=-31(0)-44[/tex]
v = -44
Hence, the correct option is, The initial velocity is -44
