Answer :
[tex]\frac{1}{2} + \frac{4}{2x} = \frac{x + 4}{10}[/tex]
[tex]\frac{x}{2x} + \frac{4}{2x} = \frac{x + 4}{10}[/tex]
[tex]\frac{x + 4}{2x} = \frac{x + 4}{10}[/tex]
[tex]10(x + 4) = 2x(x + 4)[/tex]
[tex]10(x) + 10(4) = 2x(x) + 2x(4)[/tex]
[tex]10x + 40 = 2x^{2} + 8x[/tex]
[tex]40 = 2x^{2} - 2x[/tex]
[tex]20 = x^{2} - x[/tex]
[tex]0 = x^{2} - x - 20[/tex]
[tex]0 = (x - 5)(x + 4)[/tex]
[tex]0 = x - 5\ or\ 0 = x + 4[/tex]
[tex]5 = x\ or\ -4 = x[/tex]
[tex]\frac{x}{2x} + \frac{4}{2x} = \frac{x + 4}{10}[/tex]
[tex]\frac{x + 4}{2x} = \frac{x + 4}{10}[/tex]
[tex]10(x + 4) = 2x(x + 4)[/tex]
[tex]10(x) + 10(4) = 2x(x) + 2x(4)[/tex]
[tex]10x + 40 = 2x^{2} + 8x[/tex]
[tex]40 = 2x^{2} - 2x[/tex]
[tex]20 = x^{2} - x[/tex]
[tex]0 = x^{2} - x - 20[/tex]
[tex]0 = (x - 5)(x + 4)[/tex]
[tex]0 = x - 5\ or\ 0 = x + 4[/tex]
[tex]5 = x\ or\ -4 = x[/tex]
Answer:
there are two solutions when adding your fraction- your two answers should be x=-4 and x=5, which is answer choice C for this problem! hope this helped you!
Step-by-step explanation: