Answer :
Answer:
head loss = 805.327 m
Explanation:
given data
average flow speed v = 2.5 m/s
inlet pressure Pi = 8.25 MPa
elevation Zi = 45 m
outlet pressure Po = 350 kPa
elevation Zo = 115 m
we consider oil Specific Gravity = 0.92
to find out
head loss in this section of pipeline
solution
we find here head loss that is inlet and outlet
Hi = [tex]\frac{Pi}{\rho g} +\frac{Vi^2}{2g} +Zi[/tex] ..............1
put here value
Hi = [tex]\frac{8.25*10^6}{920*9.81} +\frac{2.5^2}{2*9.81} +45[/tex]
Hi = 959.425 m
and
Hout = [tex]\frac{Pout}{\rho g} +\frac{Vout^2}{2g} +Zout[/tex] ..............2
put here value
H out = [tex]\frac{350*10^3}{920*9.81} +\frac{2.5^2}{2*9.81} +115[/tex]
H out = 154.098 m
so
head loss is = Hi - H out
head loss is = 959.425 - 154.098
head loss = 805.327 m