Answer :
Missing information
Consider a superconducting MRI magnet for which the magnet field decreases from 8.0 T to nearly 0 in 20 s
Answer:
0.152 mV
Explanation:
Change in magnetic field, dB=8-0=8 T
Time interval, dt=20 s
Diameter of ring= 2.2cm hence radius is 1.1 cm equivalent to 0.011
[tex]\epsilon=nA\frac {dB}{dt}[/tex] where n is the number of terms and for this question n=1 and A is area which is given by [tex]\pi r^{2}[/tex] hence
[tex]\epsilon=n\pi r^{2} \frac {dB}{dt}[/tex] and substituting the values
[tex]\epsilon=1\pi 0.011^{2}\times \frac {8}{20}=1.52\times 10^{-4} V=0.152 mV[/tex]
Therefore, induced emf is 0.152 mV