Answer :
[tex]\text { The force between the given two objects is } 1.865 \times 10^{-6} \mathrm{N}[/tex]
Explanation:
As per given question,
[tex]m_{1} \text { is } 140 \mathrm{kg}[/tex]
[tex]m_{2} \text { is } 160 \mathrm{kg}[/tex]
R is 0.895 m
The force between two objects is
[tex]\mathrm{F}=\frac{G m_{1} m_{2}}{R^{2}}[/tex]
Where,
F is the force of attraction between two objects in Newton’s (N)
[tex]\text { G is the Universal Gravitational Constant }=6.674 \times 10^{-11} \mathrm{N}-\mathrm{m}^{2} / \mathrm{kg}^{2}[/tex]
[tex]m_{1} \text { and } m_{2} \text { are the masses of the two objects in kilograms (kg) }[/tex]
R is the separation in meters (m) between the objects
Substitute the given values in the above formula,
[tex]F=\frac{6.674 \times 10^{-11} \times 140 \times 160}{0.895^{2}}[/tex]
[tex]F=\frac{1.494 \times 10^{-6}}{0.801}[/tex]
[tex]\mathrm{F}=1.865 \times 10^{-6}[/tex]
[tex]\text { The force between the given two objects is } 1.865 \times 10^{-6} \mathrm{N}[/tex]