Answer :

Ashraf82

The sum of the first five terms of the geometric series 8, -24, 72..... is 488 ⇒ answer B

Step-by-step explanation:

In the geometric series:

  • There is a constant ratio " r " between each two consecutive terms
  • The nth term is [tex]a_{n}=ar^{n-1}[/tex] , where a is the 1st term
  • The sum of nth terms is [tex]S_{n}=\frac{a(1-r^{n})}{1-r}[/tex]

∵ 8 , -24 , 72 , ........ is a geometric series

∵ [tex]r=\frac{a_{2}}{a_{1}}[/tex]

∵ [tex]a_{1}[/tex] = 8

∵ [tex]a_{2}[/tex] = -24

∴ [tex]r=\frac{-24}{8}[/tex]

∴ r = -3

∵ The sum of the nth terms is [tex]S_{n}=\frac{a(1-r^{n})}{1-r}[/tex]

- We need the sum of the first 5 terms, then n is 5

∵ n = 5 , a = 8 , r = -3

- Substitute these values in the rule of the sum

∴ [tex]S_{5}=\frac{8(1-(-3)^{5})}{1-(-3)}[/tex]

∴ [tex]S_{5}=\frac{8(1-(-243))}{1+3}[/tex]

∴ [tex]S_{5}=\frac{8(1+243)}{4}[/tex]

∴ [tex]S_{5}=\frac{8(244)}{4}[/tex]

∴ [tex]S_{5}=488[/tex]

The sum of the first five terms of the geometric series 8, -24, 72..... is 488

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Answer:

the answer is b

Step-by-step explanation:

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