Find the midpoint of the line segment with the given endpoints.
(6,3/5) and (-2.9./5)
The midpoint of the segment is
(Tyne an ordered nair Tyne an exact answer using radicals as need​

Answer :

Ashraf82

The mid-point of the line segment is (2 , [tex]\frac{6}{5}[/tex] )

Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are [tex](x_{1},y_{1})[/tex] and [tex](x_{2},y_{2})[/tex] , then

  • [tex]x=\frac{x_{1}+x_{2}}{2}[/tex]
  • [tex]y=\frac{y_{1}+y_{2}}{2}[/tex]

∵ The end-points of a line segment are (6 , [tex]\frac{3}{5}[/tex] ) and (-2 , [tex]\frac{9}{5}[/tex] )

∴ [tex]x_{1}[/tex] = 6 and [tex]x_{2}[/tex] = -2

∴ [tex]y_{1}[/tex] = [tex]\frac{3}{5}[/tex] and [tex]y_{2}[/tex] = [tex]\frac{9}{5}[/tex]

∵ [tex]x=\frac{x_{1}+x_{2}}{2}[/tex]

∴ [tex]x=\frac{6+(-2)}{2}[/tex]

∴ [tex]x=\frac{6-2}{2}[/tex]

∴ [tex]x=\frac{4}{2}[/tex]

∴ x = 2

∴ The x-coordinate of the mid-point is 2

∵ [tex]y=\frac{y_{1}+y_{2}}{2}[/tex]

∴ [tex]y=\frac{\frac{3}{5}+\frac{9}{5}}{2}[/tex]

∴ [tex]y=\frac{\frac{12}{5}}{2}[/tex]

∴ [tex]y=\frac{12}{10}[/tex]

- Divide up and down by 2 to reduce the fraction to its lowest value

∴ [tex]y=\frac{6}{5}[/tex]

∴ The y-coordinate of the mid-point is [tex]\frac{6}{5}[/tex]

The mid-point of the line segment is (2 , [tex]\frac{6}{5}[/tex] )

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