Answer :
Answer:
1. Expression can be rewritten as [tex]5pq[/tex] and [tex]-m+4[/tex]
2. The expression for total cost for a visit = [tex]\$10.50+ \$3.2n[/tex] and the Total Cost to visit the fair for 20 tickets is [tex]\$80.50[/tex]
3. B. [tex]-x+8[/tex]
Step-by-step explanation:
1. Solving for first Question
Given expression are [tex]8pq-3pq[/tex] and [tex]2m-3m+4[/tex]
Solving equation we get,
[tex]8pq-3pq=5pq\\2m-3m+4=-m+4[/tex]
Expression can be rewritten as [tex]5pq[/tex] and [tex]-m+4[/tex]
2. Solving for 2 Question
Given
Fixed cost of carnival = [tex]\$ 10.50[/tex]
Additional Cost per ticket for food and ride = [tex]\$ 3.50[/tex]
[tex]n[/tex] represents number of tickets.
Total cost to visit carnival = Fixed cost of carnival + Additional Cost per ticket for food and ride[tex]\times[/tex] Number of tickets = [tex]\$ 10.50+\$ 3.50n[/tex]
algebraic expression to represent the total cost for a visit to the carnival = [tex]\$ 10.50+\$ 3.50n[/tex]
Now Number of tickets sold n = 20
Total cost to visit carnival= [tex]\$ 10.50+\$ 3.50n= \$ 10.50+\$ 3.50\times20= \$ 10.50+\$ 70 =\$ 80.50[/tex]
Total Cost to visit the fair for 20 tickets is [tex]\$80.50[/tex]
3. Solving for 3 question.
Given :
[tex]\frac{8-4(x-6)}{4}[/tex]
Solving Above equation we get:
[tex]\frac{8-4(x-6)}{4}= \frac{4(2-x+6)}{4}=-x+8[/tex]
Hence the answer is B. [tex]-x+8[/tex]