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what is the value of the range of the function f(x)=x²+2 for the domain value ¼?
A. y=2
B. y=2¼
C. y=2⅛
D. y=2 1/16​

Answer :

Answer:

D.  For domain  x  =1/4  ,  [tex] y =  2\frac{1}{16}[/tex]

Step-by-step explanation:

Here, the given function is [tex]f(x) = x^2 + 2[/tex]

or we can also say that [tex]y= x^2 + 2[/tex]

Now, for domain value of x = 1/4

[tex]y(\frac{1}{4} ) = (\frac{1}{4} )^2 + 2 =  2 + \frac{1}{16 }  = 2\frac{1}{16}[/tex]

Hence, for domain  x  =1/4  ,  [tex] y =  2\frac{1}{16}[/tex]

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