PLEASE HELP!!! What is the simplified form of square root of 2160x^8/ 60x^2? Assume

Answer:
6x^3
Step-by-step explanation:
2160x^8/ 60x^2
2160/60=36
x^8-2 because your dividing
x^6
36x^6 (you're not done)
after you've got the square root
6x^3 because
36=6*6
and the square root of 6 is 2.45 which rounds to 3
(I'm pretty sure this is the answer).
The simplified form of [tex]\rm \sqrt{\dfrac{2160 x^8}{60x^2}[/tex] is 6x³ , Option C is the right answer.
Square root of a positive square number is the number itself.
[tex]\rm \sqrt{y^8} = y^4[/tex]
In the given question the expression given is
[tex]\rm \sqrt{\dfrac{2160 x^8}{60x^2}[/tex]
To simplify this
the numerator and the denominator has to be simplified first
[tex]\rm \dfrac{2160x^8}{60x^2}\\[/tex]
[tex]\rm \dfrac{2160}{60}\\ \\\\\ \dfrac{1080}{30}\\\\\\ \dfrac{540}{15} \\\\\\ \dfrac{108}{3}\\\\= 36[/tex]
[tex]\rm \dfrac{x^8}{x^2} \\\\= x^{8-2}\\\\= x^6[/tex]
Therefore
[tex]\rm \sqrt{36x^6}[/tex]
6x³
The simplified form of [tex]\rm \sqrt{\dfrac{2160 x^8}{60x^2}[/tex] is 6x³ , Option C is the right answer.
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