Answer :
Answer:
B. [tex]6n^2-12 n +8[/tex]
Step-by-step explanation:
Given,
The number of smaller cubes = [tex]n^3[/tex]
So, the number of cubes that have no coloured faces. = [tex](n-2)^3[/tex],
Note : If a cube painted outside having side n is split into n³ cubes, then the volume volume that is not painted = (n-2)³
Thus, the remaining cubes that have been painted red on at least one of their faces
= Total cubes - cubes with no painted face
[tex]= n^3 -(n-2)^3[/tex]
[tex]=n^3 - (n^3 - 8 - 6n^2 +12n)[/tex]
[tex]=6n^2-12 n +8[/tex]
Hence, OPTION B is correct.