Answer :
Answer:
It will leave the sprinkler at speed of [tex]v_2=613.87m/sec[/tex]
Step-by-step explanation:
We have given internal diameter of the garden hose [tex]d_1=0.740in=1.8796cm[/tex]
So radius [tex]r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm[/tex]
So area [tex]A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2[/tex]
Water in the hose has a speed of 4 ft/sec
So [tex]v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)[/tex]
Number of holes n = 36
Diameter of each hole [tex]d_2=0.1397cm[/tex]
So radius [tex]r_2=0.0698cm[/tex]
So area [tex]A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2[/tex]
From continuity equation
[tex]A_1v_1=nA_2v_2[/tex]
[tex]2.7733\times 121.92=36\times 0.0153\times v_2[/tex]
[tex]v_2=613.87m/sec[/tex]