Answer :
Answer:
Percentage of silver and sulphur in the compound is 87.08% and 12.91% respectively
Explanation:
Given:
Amount of silver = 29.0 g
Amount of sulphur= 4.30 g
To find:
Percent composition of the compound=?
Solution:
[tex]\text { percent of compound }=\frac{\text { amount of element }}{\text { Total Molecule Mass }} \times 100[/tex]
Total Molecule mass = amount of silver + amount of sulphur
Total Molecule mass = 29+4.3
Total Molecule mass = 33.3g
Percentage of silver:
[tex]\text { Percentage of silver }=\frac{\text { amount of silver }}{\text { Total Molecule Mass }} \times 100[/tex]
=>[tex]\frac{29.0}{33.3}\times100[/tex]
=>[tex]0.8708 \times100[/tex]
=> 87.08%
Percentage of silver:
[tex]\text { Percentage of silver }=\frac{\text {amount of suplhur}}{\text { Total Molecule Mass }} \times 100[/tex]
=>[tex]\frac{4.30}{33.3}\times 100[/tex]
=>[tex]0.1291\times 100[/tex]
=> 12.91%