Answer :
Answer:
The distance of helicopter from the injured person is 542.82 feet
Step-by-step explanation:
Given as :
The height of the hovering helicopter above the ground = h = 450 feet
The angle of elevation from injured person to helicopter = Ф = 56°
Or, Let the distance of of helicopter from person = x feet
Now, From Triangle
∵ Sin Ф = [tex]\dfrac{\textrm Perendicular}{\textrm Hypotenuse}[/tex]
∴ Sin 56° = [tex]\dfrac{\textrm h}{\textrm x}[/tex]
Or, 0.8290 = [tex]\dfrac{\textrm 450}{\textrm x}[/tex]
Or , x = [tex]\dfrac{\textrm 450}{\textrm 0.8290}[/tex]
I.e x = 542.82 feet
So, The distance from injured person to helicopter = 542.82 feet
Hence The distance of helicopter from the injured person is 542.82 feet Answer