The speed of the child is 2.21 m/s
Explanation:
The child is moving in circular motion. First of all, we find its frequency of revolution, which is given by:
[tex]f=\frac{N}{t}[/tex]
where
N = 11 is the number of revolutions
t = 25.4 s is the time elapsed
So,
[tex]f=\frac{11}{25.4}=0.433 Hz[/tex]
Now we find the angular frequency, which is given by
[tex]\omega = 2\pi f = 2\pi(0.433)=2.72 rad/s[/tex]
And now we can fidn the linear speed of the child, which is given by
[tex]v=\omega r[/tex]
where
[tex]\omega=2.72 rad/s[/tex] is the angular frequency
r = 0.811 m is the radius of the circular trajectory
Substituting,
[tex]v=(2.72)(0.811)=2.21 m/s[/tex]
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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