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In a survey conducted by a website, employers were asked if they had ever sent an employee home because they were dressed inappropriately. A total of 2755 employers responded to the survey, with 967 saying that they had sent an employee home for inappropriate attire. In a press release, the website makes the claim that more than one-third of employers have sent an employee home to change clothes. Do the sample data provide convincing evidence in support of this claim? Test the relevant hypotheses using α = 0.05. For purposes of this exercise, assume that it is reasonable to regard the sample as representative of employers in the United States. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = Incorrect: Your answer is incorrect. P-value =

Answer :

Answer:

Test statistic Z = p diff/std error = 2.3333

p value one tailed = 0.009815

Step-by-step explanation:

Given that in a survey conducted by a website, employers were asked if they had ever sent an employee home because they were dressed inappropriately.

Sample size n = 2755

Sample favourable x = 967

Sample proportion p = [tex]\frac{967}{2755} \\=0.3510[/tex]

[tex]H_0: p = 0.3333\\H_a: p >0.3333[/tex]

(right tailed test at 5% significance level)

p difference = 0.0210

Standard error assuming H0 is true is [tex]\sqrt{\frac{0.3333*0.6667}{2755} } \\=0.0090[/tex]

Test statistic Z = p diff/std error = 2.3333

p value one tailed = 0.009815

Since p <0.05 we reject null hypothesis.

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