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A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. The piston is now pulled up, expanding the gas, until the gas has a final volume of 45.0L. Calculate the final pressure of the gas. Be sure your answer has the correct number of significant digits.

Answer :

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law  

[tex] {P_1}\times {V_1}={P_2}\times {V_2}[/tex]

Given ,  

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]

[tex]{96.0\ kPa}\times {10.0\ L}={P_2}\times {45.0\ L}[/tex]

[tex]{P_2}=\frac {{96.0}\times {10.0}}{45.0}\ kPa[/tex]

[tex]{P_2}=21.3\ kPa[/tex]

The final pressure of the gas is:- 21.3 kPa

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