Answer :

Answer:

The zeroes of the given equation are x = √2 , -√2 , 2 , -2.

Step-by-step explanation:

The given quadratic equation is y = [tex]x^{4}- 6x^{2}+8[/tex]

To find the zeroes , put y = 0.

[tex]x^{4}- 6x^{2}+8[/tex] = 0

Put [tex]x^{2}[/tex]=t

The new equation is [tex]t^{2} -6t +8=0[/tex]

On factorising ,

[tex](t - 4)\times(t - 2)=0[/tex]

Hence t = 2 or t = 4

On resubstituting the value of t in terms of x ,

[tex]x^{2}[/tex] = 2 or [tex]x^{2}[/tex] = 4

Taking square root of above equation , we get

x = √2,-√2,2,-2

These are the 4 roots of the given equation .

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