Answered

A linear relationship exists between the natural logarithm of the vapor pressure of a gas and the reciprocal of its temperature (in kelvin). What is the slope of the line?

Answer :

Answer:

[tex]\dfrac{-\Delta{H_{vap}}}{R}[/tex]

Explanation:

The expression for Clausius-Clapeyron Equation is shown below as:

[tex]\ln P = \dfrac{-\Delta{H_{vap}}}{RT} + c [/tex]

Where,  

P is the vapor pressure

ΔHvap  is the Enthalpy of Vaporization

R is the gas constant (8.314×10⁻³ kJ /mol K)

c is the constant.

THus, the slope of the line when natural logarithm of the vapor pressure of a gas is taken at y axis and the reciprocal of its temperature is taken at x axis is:- [tex]\dfrac{-\Delta{H_{vap}}}{R}[/tex]

Other Questions