Answer :
Answer:
The function 2 has a larger maximum.
Step-by-step explanation:
The vertex form of the parabola is
[tex]f(x)=a(x-h)^2+k[/tex] .... (1)
Where, (h,k) is the vertex.
The given functions are
[tex]f(x)=-3x^2+2[/tex] ..... (2)
Since the leading coefficient is negative, therefore it is a downward parabola. It means the vertex of the parabola is the maximum point.
On comparing (1) and (2), we get
[tex]h=0,k=2[/tex]
Therefore the maximum value of the function is 2 at x=0.
The second function has x intercepts of (-0.5, 0) and (2, 0) and a vertex of (0.5, 4).
It is also a downward parabola because the parabola has two x-intercepts and the vertex lies above the x-axis.
Since the vertex is (0.5, 4), therefore the maximum value of the function is 4 at x=0.5.
[tex]Maximum(F_1)=2[/tex]
[tex]Maximum(F_2)=4[/tex]
Therefore function 2 has a larger maximum.
