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A solid colored, short-haired female rabbit (ssLL) is mated to a spotted, long-haired
male (SSll). The F1 offspring are allowed to interbreed and 64 offspring are produced.
c) How many will be spotted with long hair?
d) How many will be solid-colored and short-haired?

Answer :

Answer:

Spotted with long hair⇒ 12

Solid colored and short hair⇒ 12

Explanation:

Both genotypes are homozygote type. So, they will produce only one type of gamete from each. that are sL and Sl.

The genotype of F1 offspring will SsLl ( spotted short hair, heterozygote)

when F1 offsprings are interbreeded four types of phenotype are produced.

they are

  1. spotted short haired ⇒ [tex]\frac{36}{64}[/tex] (dominant type)
  2. spotted long hair ⇒ [tex]\frac{12}{64}[/tex]
  3. solid colored short hair⇒ [tex]\frac{12}{64}[/tex]
  4. solid colored long hair⇒ [tex]\frac{4}{64}[/tex]
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