Answer :
Answer:0.0106 m
Explanation:
Given
Absolute Pressure at the bottom is [tex]P=1.1 atm[/tex]
Height of cylinder is [tex]h=0.9 m[/tex]
Density of mercury [tex]\rho _{hg}=13.6\times 10^{3} kg/m^3[/tex]
Pressure Difference is given by
[tex]\Delta P=\rho g\cdot h_0[/tex]
Pressure at bottom=Pressure at Top+Pressure due to mercury and water
[tex]1.1\times 1.0132\times 10^5=1.01325\times 10^5+\rho _w\times 9.8\times (0.9-d)+\rho _{hg}\times 9.8\times d[/tex]
converting Pressure into KPa
[tex]111.45=101.325+9.8\cdot (0.9-d)+13.6\cdot 9.8\cdot d[/tex]
[tex]\frac{10.13}{9.8}=0.9 -d +13.6 d[/tex]
[tex]d=0.0106 m[/tex]