A skydiver jumps from a plane from an altitude of 6000 ft. An observer on the ground measures the skydiver's altitude at time t =0 to be 4500 ft. The linear graph shows the skydiver's altitude at various times during her descent. Answer Questions part A, part B, part C and part D. Will Mark Brainliest ​

A skydiver jumps from a plane from an altitude of 6000 ft. An observer on the ground measures the skydiver's altitude at time t =0 to be 4500 ft. The linear gra class=

Answer :

Answer:

a. (0,4500)

b. Slope = - 1500 meters/ minute.

c. (3,0)

d. y = 4500 - 1500x

Step-by-step explanation:

2. See the linear graph that shows the sky diver's altitude at various times during her descent.

a. The y-intercept of the graph is at (0,4500) point.

The skydiver jumps from a plane from an altitude of 6000 meters and the observer on the ground measures the altitude of 4500 meters at time = 0 minutes.

Therefore, the observer starts to measure the altitude after some time of her jump.

b. (0,4500) and (1, 3000) are the points through which the straight line passes.

Therefore, the slope of the line is [tex]\frac{4500 - 3000}{0 - 1} = - 1500[/tex].

Hence, the slope is negative and that means that the skydiver is descending and the rate of descent is - 1500 meters per minute.

c. We require the point of x-intercept of the graph and it is at (3,0).  

This means that the diver touches the ground after 3 minutes.

d. (0,4500) and (1, 3000) are the points through which the straight line passes.

Therefore, the equation of the line will be  

[tex]\frac{y - 4500}{4500 - 3000} = \frac{x - 0}{0 - 1}[/tex]

⇒ y = 4500 - 1500x (Answer)

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