A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction between the ice and the skates?
The horizontal force : f = k*N k- coefficient of friction k = f /N N = m * g = 45 kg * 9.81 m/s² = 441.45 N k = 25 N : 441.45 N = 0.057 Answer C) 0.057
