Answer :
Explanation:
It is given that,
Radius of the circular track, r = 25 m
Mass of the go cart with the rider, m = 200 kg
The magnitude of the maximum centripetal force exerted by the track on the go-cart is 1200 N.
The centripetal force exerted by the track o the go cart is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
v is the maximum speed at which the go-cart could travel without sliding off this track.
[tex]v=\sqrt{\dfrac{Fr}{m}}[/tex]
The maximum speed is directly proportional to the force and radius of track. On increasing force and radius and decreasing the mass would increase maximum speed. It is given by :
[tex]v=\sqrt{\dfrac{1200\times 25}{200}}[/tex]
v = 12.24 m/s
Hence, this is the required solution.