Answer :
Answer:
0.104 m
Explanation:
Stress, [tex]\sigma=\frac {F}{A}[/tex]
Where F is force and A is area. Also, F=mg where m is mass and g is acceleration due to gravity
[tex]Area= \pi r^{2}[/tex]
[tex]Strain=\frac {\triangle l}{l}[/tex] where [tex]\triangle l[/tex] is the elongation and l is the original length
[tex]E=\frac {stress}{strain}=\frac {\frac {F}{A}}{\frac {\triangle l}{l}}=\frac {Fl}{A\triangle l}[/tex]
Making [tex]\triangle l[/tex] the subject then
[tex]\triangle l=\frac {Fl}{AE}=\frac{mg l}{\pi r^{2} E}[/tex]
By substituting the given values and taking g as 9.81 then
[tex]\triangle l=\frac {Fl}{AE}=\frac{500\times 9.81\times 2 m}{\pi \times 0.005^{2}\times 1.2\times 10^{9}}=0.104087333 m\approx 0.104 m[/tex]