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For 0.37 moles of oxygen (O2) gas at room temperature with active translational and rotational degrees of freedom. How much heat must be added to in order to raise its temperature by 15 K with the pressure kept constant?a. 100.4Jb. 161.5J c. 69.2J d. 19.4J e. 935.3J

Answer :

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To solve this problem we will use the concept given for the exchange of heat given based on the number of moles, the specific heat and the temperature change.

[tex]Q = nC_p \Delta T[/tex]

Where,

[tex]C_p[/tex] = Specific Heat

[tex]\Delta T[/tex]= Change in temperature

n = Number of moles

For diatomic and polyatomic ideal gases we get: diaatomic: [tex]C_p = \frac{7}{2} R[/tex]

Here R is the Gas ideal Constant,

Therefore replacing we have,

[tex]Q = n \frac{7}{2}R \Delta T[/tex]

[tex]Q = (0.37)(\frac{7}{2})(8.414)(15)[/tex]

[tex]Q = 161.5J[/tex]

The correct answer is B.

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