Answer :
Answer:
Step-by-step explanation:
Given
radius of sphere [tex]R=13\ units[/tex]
Hole is drilled with radius [tex]r=9\ units[/tex]
Now this drilled hole will be in the form of Cylinder with height equals to diameter of sphere thus
Volume of drilled hole is
[tex]V_d=\pi \cdot r^2\cdot h[/tex]
[tex]V_d=\pi \cdot (9)^2\cdot 26[/tex]
[tex]V_d=2106\pi [/tex]
Volume of Sphere
[tex]V_s=\frac{4}{3}\pi R^3[/tex]
[tex]V_s=\frac{4}{3}\pi (13)^3[/tex]
[tex]V_s=2929.33\pi [/tex]
Remaining volume [tex]V_{remaining}=2929.33\pi -2106\pi =823.33\pi [/tex]
[tex]V_{remaining}=2586.90\ units^3[/tex]